http://www.k-wave.org/forum/topic/absorption-in-pstdelastic2d Support for the k-Wave MATLAB toolbox en-US Tue, 12 May 2026 23:28:24 +0000 http://bbpress.org/?v=1.0.2 q http://www.k-wave.org/forum/search.php http://www.k-wave.org/forum/topic/absorption-in-pstdelastic2d#post-7266 Wed, 04 Mar 2020 23:00:09 +0000 elliotP 7266@http://www.k-wave.org/forum/ <p>Dr. Treeby,</p> <p>Thank you for your suggestion. Actually, I think there are different numbers for attenuation and approaches for the skull simulations. For example, the skull is modeled as a uniform medium in one of your papers which you used shear attenuation 19.5 dB/(MHz^2 cm) and compressional attenuation 8.83 dB/(MHz^2 cm).</p> <p>Best,<br /> Michael </p> http://www.k-wave.org/forum/topic/absorption-in-pstdelastic2d#post-7258 Wed, 04 Mar 2020 11:50:35 +0000 Bradley Treeby 7258@http://www.k-wave.org/forum/ <p>Yes, that seems correct if you can assume an f^2 frequency dependence. Note, the value of 13.3 dB/cm is for the total attenuation (including scattering). If you want to use the Pinton values in <code>pstdElastic2D</code>, I would suggest using the actual absorption values, which are 2.7 dB/cm for the compression absorption and 5.4 dB/cm for the shear absorption. </p> http://www.k-wave.org/forum/topic/absorption-in-pstdelastic2d#post-7254 Wed, 04 Mar 2020 07:02:19 +0000 elliotP 7254@http://www.k-wave.org/forum/ <p>Hi all,</p> <p>In the paper below, bone attenuation is measured 13.3 dB/cm at 1 MHz. I want to use this attenuation value in pstdElastic2D simulation which attenuation unit is dB/(MHz^2 cm). So, I divided 13.3 by 1^2 and I got 13.3 dB/(MHz^2 cm). </p> <p>Do you think it is a correct way to get the attenuation from the dB/cm unit? </p> <p>Best,<br /> Michael</p> <p>[1]Pinton, Gianmarco, et al. "Attenuation, scattering, and absorption of ultrasound in the skull bone." Medical physics 39.1 (2012): 299-307. </p>