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		<title>k-Wave User Forum &#187; Topic: Absorption Model</title>
		<link>http://www.k-wave.org/forum/topic/absorption-model</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
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		<pubDate>Tue, 12 May 2026 23:28:19 +0000</pubDate>
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			<title>vich on "Absorption Model"</title>
			<link>http://www.k-wave.org/forum/topic/absorption-model#post-7072</link>
			<pubDate>Tue, 08 Oct 2019 20:43:55 +0000</pubDate>
			<dc:creator>vich</dc:creator>
			<guid isPermaLink="false">7072@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;There's only so much you can do with limited information. If you know the attenuation (in dB/cm) the authors reported and the frequency (in MHz) of the ultrasound in their experiments, you could simply divide the attenuation by the frequency squared. There is no way to know if your power law exponent of 2 is correct, though.&#60;/p&#62;
&#60;p&#62;If the authors provided multiple attenuation values at different frequencies, you can fit a power regression model to the data points. This essentially means fitting the parameters a, b in:&#60;/p&#62;
&#60;p&#62;&#60;code&#62;&#60;br /&#62;
log(attenuation) = a + b * log(frequency)&#60;br /&#62;
&#60;/code&#62;&#60;/p&#62;
&#60;p&#62;via ordinary least squares. Once the parameters have been estimated, you can take an exponential to get:&#60;/p&#62;
&#60;p&#62;&#60;code&#62;&#60;br /&#62;
exp(log(attenuation)) = exp(a + b * log(frequency))&#60;br /&#62;
attenuation = exp(a) * exp(log(frequency)) ^ b&#60;br /&#62;
attenuation = exp(a) * frequency ^ b&#60;br /&#62;
&#60;/code&#62;&#60;/p&#62;
&#60;p&#62;When using k-Wave, &#60;code&#62;exp(a)&#60;/code&#62; becomes &#60;code&#62;medium.alpha_coeff&#60;/code&#62; and &#60;code&#62;b&#60;/code&#62; becomes &#60;code&#62;medium.alpha_power&#60;/code&#62;.&#60;/p&#62;
&#60;p&#62;Perhaps other people here might have different suggestions?
&#60;/p&#62;</description>
		</item>
		<item>
			<title>elliotP on "Absorption Model"</title>
			<link>http://www.k-wave.org/forum/topic/absorption-model#post-7057</link>
			<pubDate>Mon, 23 Sep 2019 00:55:17 +0000</pubDate>
			<dc:creator>elliotP</dc:creator>
			<guid isPermaLink="false">7057@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hello everyone,&#60;/p&#62;
&#60;p&#62;Unit of the absorption coefficient for compressional waves and shear waves is dB/(MHz^2 cm) in a pstdElastic2D simulation (power-law exponent is set to y = 2).&#60;br /&#62;
When I look for papers which are related to a transcranial application, authors use dB/cm unit such as 13.3 dB/cm (paper name: Attenuation, scattering, and absorption of ultrasound in the skull bone.)&#60;br /&#62;
How can I convert dB/cm to dB/(MHz^2 cm)?&#60;/p&#62;
&#60;p&#62;Thank you,&#60;br /&#62;
Michael
&#60;/p&#62;</description>
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