http://www.k-wave.org/forum/topic/calculating-strength-of-echo-response Support for the k-Wave MATLAB toolbox en-US Wed, 13 May 2026 06:53:55 +0000 http://bbpress.org/?v=1.0.2 q http://www.k-wave.org/forum/search.php http://www.k-wave.org/forum/topic/calculating-strength-of-echo-response#post-7741 Wed, 19 Aug 2020 14:35:02 +0000 Bradley Treeby 7741@http://www.k-wave.org/forum/ <p>Hi vibhav,</p> <p>You could have a look at the Time Varying Source Problems examples, in particular <a href="http://www.k-wave.org/documentation/example_tvsp_snells_law.php">Snell's Law And Critical Angle Reflection Example</a> (you can open these in the MATLAB help browser).</p> <p>For this particular setup, the <a href="http://www.elasticmatrix.org">ElasticMatrix</a> toolbox may also be useful.</p> <p>Brad </p> http://www.k-wave.org/forum/topic/calculating-strength-of-echo-response#post-7705 Thu, 23 Jul 2020 12:35:49 +0000 vibhav 7705@http://www.k-wave.org/forum/ <p>Hi all,<br /> I am trying to build a simulation, that would simulate the propagation of an ultrasound wave (5-20 Mhz) through a multi-layered stackup(3-4 mediums), where thick of each medium is 1-5 mm, below is a basic diagram depicting the same. An object would be placed at the end of the stack, that would reflect back 90% of the incoming signal. I am doing this by adjusting the speed of sound at the end, such that reflection coefficient at the end is 0.9. The goal here is to measure the strength of the echo response obtained after the round-trip transmission. I wanted to know how I should go about coding this into K-wave. Any advice would be helpful.<br /> Thanks in advance</p> <p>%------------------------------</p> <p> Source/Receiver</p> <p>---------Medium 1------------<br /> - speed(c1),density(d1) -<br /> - thickness(t1) -<br /> ---------Medium 2------------<br /> - speed(c2),density(d2) -<br /> - thickness(t2) -<br /> - -<br /> ~ ~<br /> ~ ~<br /> - -<br /> ---------Medium n------------<br /> - speed(cn),density(dn) -<br /> - thickness(tn) -<br /> -----Object(reflect 90%)----- </p>