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		<title>k-Wave User Forum &#187; Topic: Define a circular phased array ultrasound transducer with 16 elements</title>
		<link>http://www.k-wave.org/forum/topic/define-a-circular-phased-array-ultrasound-transducer-with-16-elements</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
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		<pubDate>Wed, 13 May 2026 17:21:28 +0000</pubDate>
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			<title>Bradley Treeby on "Define a circular phased array ultrasound transducer with 16 elements"</title>
			<link>http://www.k-wave.org/forum/topic/define-a-circular-phased-array-ultrasound-transducer-with-16-elements#post-6236</link>
			<pubDate>Tue, 12 Dec 2017 22:46:34 +0000</pubDate>
			<dc:creator>Bradley Treeby</dc:creator>
			<guid isPermaLink="false">6236@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi liuhao,&#60;/p&#62;
&#60;p&#62;Unfortunately it's not possible to use the &#60;code&#62;kWaveTransducer&#60;/code&#62; class in this way (only linear arrays are supported). For other geometries, you will need to define the sources and sensors directly using &#60;code&#62;source.p_mask&#60;/code&#62; (or &#60;code&#62;source.u_mask&#60;/code&#62;) and &#60;code&#62;sensor.mask&#60;/code&#62;.&#60;/p&#62;
&#60;p&#62;Brad.
&#60;/p&#62;</description>
		</item>
		<item>
			<title>liuhao on "Define a circular phased array ultrasound transducer with 16 elements"</title>
			<link>http://www.k-wave.org/forum/topic/define-a-circular-phased-array-ultrasound-transducer-with-16-elements#post-6221</link>
			<pubDate>Thu, 07 Dec 2017 06:37:44 +0000</pubDate>
			<dc:creator>liuhao</dc:creator>
			<guid isPermaLink="false">6221@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hello, Dr. Bradley Treeby&#60;/p&#62;
&#60;p&#62;I am a new guy in Ultrasonic Imaging, I might have the same problem on circle transducers.&#60;/p&#62;
&#60;p&#62;I need to build 128 transducers on the boundary of a circle area, and using them both as transducers and sensors. I noticed that in &#34;makeTransducer&#34; part of the User's guide, the &#34;tr.radius&#34; should be inf, but how can I put them in a circle way?&#60;/p&#62;
&#60;p&#62;Thank you very much!
&#60;/p&#62;</description>
		</item>
		<item>
			<title>Bradley Treeby on "Define a circular phased array ultrasound transducer with 16 elements"</title>
			<link>http://www.k-wave.org/forum/topic/define-a-circular-phased-array-ultrasound-transducer-with-16-elements#post-5666</link>
			<pubDate>Fri, 09 Sep 2016 21:25:24 +0000</pubDate>
			<dc:creator>Bradley Treeby</dc:creator>
			<guid isPermaLink="false">5666@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi CHEN SIYU,&#60;/p&#62;
&#60;p&#62;When using &#60;code&#62;imrotate&#60;/code&#62; in MATLAB, the output matrix will not be the same size as the input. You need to add the option &#60;code&#62;&#38;#39;crop&#38;#39;&#60;/code&#62; and it should work.&#60;/p&#62;
&#60;p&#62;Regarding your second option, I'm not sure what the line of code &#60;code&#62;source_shape2(180-50sin(pi/8:360, :);&#60;/code&#62; does.&#60;/p&#62;
&#60;p&#62;Hope that helps,&#60;/p&#62;
&#60;p&#62;Brad.
&#60;/p&#62;</description>
		</item>
		<item>
			<title>CHEN SIYU on "Define a circular phased array ultrasound transducer with 16 elements"</title>
			<link>http://www.k-wave.org/forum/topic/define-a-circular-phased-array-ultrasound-transducer-with-16-elements#post-5656</link>
			<pubDate>Fri, 02 Sep 2016 07:45:11 +0000</pubDate>
			<dc:creator>CHEN SIYU</dc:creator>
			<guid isPermaLink="false">5656@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;hello, can anybody hello me solve the problems?&#60;br /&#62;
I wanna define a circular phased array ultrasound with 16 elements and the focus point is at center of the circle.&#60;br /&#62;
I have two methods to approach problem.&#60;br /&#62;
the below is Matlab code.&#60;br /&#62;
1:define one element of the transducer.&#60;br /&#62;
source_shape1  = makeCircle(Nx, Ny, 0, 0, 100, pi/8);&#60;br /&#62;
2:Rotate source_shape1 about pi/8 as the second element&#60;br /&#62;
source_shape2 = imrotate(source_shape1, pi/8)&#60;br /&#62;
2:Rotate source_shape1 about pi/8 as the third element&#60;br /&#62;
source_shape3 = imrotate(source_shape2, pi/8)&#60;br /&#62;
..........................&#60;br /&#62;
16:source_shape16 = imrotate(source_shape2, pi/8);&#60;/p&#62;
&#60;p&#62;add all the source_shape together&#60;/p&#62;
&#60;p&#62;but Matlab generate:&#60;br /&#62;
Error using  +&#60;br /&#62;
Matrix dimensions must agree.&#60;/p&#62;
&#60;p&#62;The second approach:Nx = Ny = 360&#60;br /&#62;
define the first elements&#60;br /&#62;
source_shape1  = makeCircle(Nx, Ny, 0, 0, 100, pi/8);&#60;br /&#62;
define the second element&#60;br /&#62;
source_shape2  = makeCircle(Nx, Ny, 0, 0, 100, pi/4);&#60;br /&#62;
cut the unwanted element of the source_shape2&#60;br /&#62;
source_shape2(180-50sin(pi/8:360, :);&#60;br /&#62;
source_shape3 use the same method as source_shape2;&#60;/p&#62;
&#60;p&#62;add all the source_shapes together&#60;br /&#62;
source.p_mask = zeros(Nx, Ny);&#60;br /&#62;
source.p_mask(:, :) = source_shape1 + source_shape2 + ...........source.shape16 ;&#60;br /&#62;
but output of the matlab only come out the largest element, why?
&#60;/p&#62;</description>
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