<?xml version="1.0" encoding="UTF-8"?>
<!-- generator="bbPress/1.0.2" -->
<rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom">
	<channel>
		<title>k-Wave User Forum &#187; Topic: Defining Radius and Diameter for makeArc in k-Wave with Non-Isotropic Grids</title>
		<link>http://www.k-wave.org/forum/topic/defining-radius-and-diameter-for-makearc-in-k-wave-with-non-isotropic-grids</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
		<language>en-US</language>
		<pubDate>Thu, 14 May 2026 00:04:31 +0000</pubDate>
		<generator>http://bbpress.org/?v=1.0.2</generator>
		<textInput>
			<title><![CDATA[Search]]></title>
			<description><![CDATA[Search all topics from these forums.]]></description>
			<name>q</name>
			<link>http://www.k-wave.org/forum/search.php</link>
		</textInput>
		<atom:link href="http://www.k-wave.org/forum/rss/topic/defining-radius-and-diameter-for-makearc-in-k-wave-with-non-isotropic-grids" rel="self" type="application/rss+xml" />

		<item>
			<title>JW Kwon on "Defining Radius and Diameter for makeArc in k-Wave with Non-Isotropic Grids"</title>
			<link>http://www.k-wave.org/forum/topic/defining-radius-and-diameter-for-makearc-in-k-wave-with-non-isotropic-grids#post-9189</link>
			<pubDate>Tue, 25 Feb 2025 16:34:24 +0000</pubDate>
			<dc:creator>JW Kwon</dc:creator>
			<guid isPermaLink="false">9189@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi. I'm using k-Wave's makeArc function to generate an arc-shaped source. My simulation grid, however, is non-isotropic; the x-direction has a spacing of dx (with Nx voxels) and the y-direction has a spacing of dy (with Ny voxels), and dx ≠ dy. In this case, how should I define the radius and diameter in voxel units? Specifically, on which axis should the voxel count for the radius and diameter be based to ensure that the physical dimensions of the arc are correctly represented? Any insights or examples would be greatly appreciated.
&#60;/p&#62;</description>
		</item>

	</channel>
</rss>
