http://www.k-wave.org/forum/topic/field-of-view-in-the-linear-us-example Support for the k-Wave MATLAB toolbox en-US Tue, 12 May 2026 21:37:17 +0000 http://bbpress.org/?v=1.0.2 q http://www.k-wave.org/forum/search.php http://www.k-wave.org/forum/topic/field-of-view-in-the-linear-us-example#post-9063 Wed, 20 Mar 2024 20:42:39 +0000 Bradley Treeby 9063@http://www.k-wave.org/forum/ <p>Have you looked at the <a href="http://www.k-wave.org/documentation/example_us_bmode_linear_transducer.php">documentation</a>? In short, a larger phantom is defined, and only a subset of this is used for each simulation to improve computational speed. </p> http://www.k-wave.org/forum/topic/field-of-view-in-the-linear-us-example#post-9040 Mon, 19 Feb 2024 00:43:40 +0000 pamparana 9040@http://www.k-wave.org/forum/ <p>I hope someone can reply to this query as I am quite confused.</p> <p>So the transducer is put in the centre of the computation grid.The width of the FOV is the number of scan lines * width of the element.</p> <p>However, I am confused as to why the FOV starts at 1 + Ny/2 rather than 1 + Ny/2 - transducer_width / 2. </p> http://www.k-wave.org/forum/topic/field-of-view-in-the-linear-us-example#post-9037 Tue, 13 Feb 2024 10:43:41 +0000 pamparana 9037@http://www.k-wave.org/forum/ <p>How is the field of view calculated for the B-mode image generation? I see in the code the following in the plotting code:</p> <pre><code>sound_speed_map(:, 1 + Ny/2:end - Ny/2, Nz/2)</code></pre> <p>So the transducer was set to be at the midpoint. So, should the field of view not be something like:</p> <pre><code>startIdx = Ny/2 - transducer_width/2 sound_speed_map(:, startIdx:startIdx + transducer_width, Nz/2)</code></pre> <p>Would really appreciate any clarification on this. </p>