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		<title>k-Wave User Forum &#187; Topic: How to convert scan-lines in polar coordinates to a B-mode ultrasound image ?</title>
		<link>http://www.k-wave.org/forum/topic/how-to-convert-scan-lines-in-polar-coordinates-to-a-b-mode-ultrasound-image</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
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		<pubDate>Tue, 12 May 2026 23:43:27 +0000</pubDate>
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			<title>Bradley Treeby on "How to convert scan-lines in polar coordinates to a B-mode ultrasound image ?"</title>
			<link>http://www.k-wave.org/forum/topic/how-to-convert-scan-lines-in-polar-coordinates-to-a-b-mode-ultrasound-image#post-8649</link>
			<pubDate>Tue, 08 Nov 2022 10:27:10 +0000</pubDate>
			<dc:creator>Bradley Treeby</dc:creator>
			<guid isPermaLink="false">8649@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi Han,&#60;/p&#62;
&#60;p&#62;The documentation should guide you how to use it. You need your data, sampling parameters, and the angles of the scan lines. What bit are you stuck on? &#60;/p&#62;
&#60;p&#62;Brad.
&#60;/p&#62;</description>
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			<title>hanhg95 on "How to convert scan-lines in polar coordinates to a B-mode ultrasound image ?"</title>
			<link>http://www.k-wave.org/forum/topic/how-to-convert-scan-lines-in-polar-coordinates-to-a-b-mode-ultrasound-image#post-8630</link>
			<pubDate>Thu, 13 Oct 2022 07:29:04 +0000</pubDate>
			<dc:creator>hanhg95</dc:creator>
			<guid isPermaLink="false">8630@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi All,&#60;/p&#62;
&#60;p&#62;If i have a raw data of ultrasound image (polar cordinate). Now I want conmvert to XY cordinate.&#60;/p&#62;
&#60;p&#62;How can I use this tool to covert ? &#60;a href=&#34;http://www.k-wave.org/documentation/scanConversion.php&#34; rel=&#34;nofollow&#34;&#62;http://www.k-wave.org/documentation/scanConversion.php&#60;/a&#62;&#60;/p&#62;
&#60;p&#62;my exaple image: &#60;a href=&#34;https://cdn.hackaday.io/images/7317421464689659964.jpg&#34; rel=&#34;nofollow&#34;&#62;https://cdn.hackaday.io/images/7317421464689659964.jpg&#60;/a&#62;&#60;/p&#62;
&#60;p&#62;Thanks and Regards&#60;br /&#62;
Han
&#60;/p&#62;</description>
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