<?xml version="1.0" encoding="UTF-8"?>
<!-- generator="bbPress/1.0.2" -->
<rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom">
	<channel>
		<title>k-Wave User Forum &#187; Topic: Maximum frequency on a given grid in several dimensions</title>
		<link>http://www.k-wave.org/forum/topic/maximum-frequency-on-a-given-grid-in-several-dimensions</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
		<language>en-US</language>
		<pubDate>Tue, 12 May 2026 23:28:21 +0000</pubDate>
		<generator>http://bbpress.org/?v=1.0.2</generator>
		<textInput>
			<title><![CDATA[Search]]></title>
			<description><![CDATA[Search all topics from these forums.]]></description>
			<name>q</name>
			<link>http://www.k-wave.org/forum/search.php</link>
		</textInput>
		<atom:link href="http://www.k-wave.org/forum/rss/topic/maximum-frequency-on-a-given-grid-in-several-dimensions" rel="self" type="application/rss+xml" />

		<item>
			<title>Bradley Treeby on "Maximum frequency on a given grid in several dimensions"</title>
			<link>http://www.k-wave.org/forum/topic/maximum-frequency-on-a-given-grid-in-several-dimensions#post-5390</link>
			<pubDate>Tue, 16 Feb 2016 02:39:57 +0000</pubDate>
			<dc:creator>Bradley Treeby</dc:creator>
			<guid isPermaLink="false">5390@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi Anthony,&#60;/p&#62;
&#60;p&#62;Interesting question! If you consider the grid geometrically, it would seem that the points are spaced further apart in the diagonal direction, and therefore would support a lower maximum frequency.&#60;/p&#62;
&#60;p&#62;However, if you think about the wave propagation in k-space, the wave field is broken into a sum of plane waves propagating in different directions. These directions are given by the values of kx and ky. Because the discrete k-space grid is square, the grid actually supports slightly higher maximum frequencies in the diagonal directions, as the corners of the k-space have a higher wavenumber than the limits of the vertical and horizontal axes.&#60;/p&#62;
&#60;p&#62;Hope that helps,&#60;/p&#62;
&#60;p&#62;Brad,
&#60;/p&#62;</description>
		</item>
		<item>
			<title>Anthony on "Maximum frequency on a given grid in several dimensions"</title>
			<link>http://www.k-wave.org/forum/topic/maximum-frequency-on-a-given-grid-in-several-dimensions#post-5331</link>
			<pubDate>Fri, 27 Nov 2015 11:09:35 +0000</pubDate>
			<dc:creator>Anthony</dc:creator>
			<guid isPermaLink="false">5331@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hello everyone,&#60;/p&#62;
&#60;p&#62;I have a question about the maximum frequency which can be propagated in several dimensions. In 1D, Shannon-Nyquist says that you need at least two points per wavelength.&#60;/p&#62;
&#60;p&#62;But, in 2D, if you wave does not propagate in the direction of your basis vectors, don't you need up to 2*sqrt(2) points per wavelength ? (and 2*sqrt(3) in 3D...) ? Am I right?  &#60;/p&#62;
&#60;p&#62;Best regards,&#60;br /&#62;
Anthony&#60;/p&#62;
&#60;p&#62;EDIT:  Sorry, I just made the calculations on a rectangular grid with Peterson-Middleton theorem and it seems enough to have two points per wavelength :-) It seems counter-intuitive to me though... Anyway, sorry, I shouldn't have posted ;-)
&#60;/p&#62;</description>
		</item>

	</channel>
</rss>
