http://www.k-wave.org/forum/topic/maybe-its-a-bug-or-something Support for the k-Wave MATLAB toolbox en-US Tue, 12 May 2026 23:08:05 +0000 http://bbpress.org/?v=1.0.2 q http://www.k-wave.org/forum/search.php http://www.k-wave.org/forum/topic/maybe-its-a-bug-or-something#post-338 Wed, 29 Feb 2012 05:21:29 +0000 Bradley Treeby 338@http://www.k-wave.org/forum/ <p>This issue should now be resolved in the latest k-Wave release (B.0.5). </p> http://www.k-wave.org/forum/topic/maybe-its-a-bug-or-something#post-268 Fri, 23 Dec 2011 01:38:39 +0000 Bradley Treeby 268@http://www.k-wave.org/forum/ <p>Hi Guoping Chen,</p> <p>Thanks for your feedback, well spotted! This indeed looks like a bug. The correct indexing should be:</p> <p><code>source.p(p_index, :) =</code><br /> <code>source.p(p_index, :) .*(dt./(c(ps_index(p_index)).*kgrid.dx));</code></p> <p>And similarly using <code>us_index</code> for the velocity sources. We'll update the codes and release a bug fix.</p> <p>Kind regards,</p> <p>Brad. </p> http://www.k-wave.org/forum/topic/maybe-its-a-bug-or-something#post-265 Thu, 22 Dec 2011 21:49:36 +0000 chenguoping 265@http://www.k-wave.org/forum/ <p>Hi,<br /> K-wave is a good works, but some details trouble me, or it is a bug.<br /> codes:<br /> for p_index = 1:length(source.p(:,1))<br /> source.p(p_index, :) = source.p(p_index, :) .* (dt./(c(p_index).*kgrid.dx));<br /> end</p> <p> in line 616 of the kspaceFirstOrder2D, the aim of the author is :<br /> % compute the scale parameter seperately for each source position<br /> % based on the sound speed at that position<br /> But I think that the p_index to the c matrix can't reach the correctly positon of the source.<br /> For example, when the source located in a circle line, and the struction of the source.p only a two dimension matrix, but the c is a 256*256 matrix, the code c(p_index) maybe not right?<br /> In addtionally, would your can explain the equation of line 616 clearly to me? Thanks very much!</p> <p> Sincerely,<br /> ECE DUKE,Guoping Chen<br /> 22th, Dec., 2011 </p>