http://www.k-wave.org/forum/topic/photoacoustic-signal-strength Support for the k-Wave MATLAB toolbox en-US Tue, 12 May 2026 23:36:23 +0000 http://bbpress.org/?v=1.0.2 q http://www.k-wave.org/forum/search.php http://www.k-wave.org/forum/topic/photoacoustic-signal-strength#post-768 Wed, 19 Sep 2012 12:57:17 +0000 manojitpramanik 768@http://www.k-wave.org/forum/ <p>Hi Ben,<br /> You are so right. I intended to use 3D, but ended up using the 2D function. It does match 1/sqrt(r) fall off.</p> <p>thank you.<br /> manojit </p> http://www.k-wave.org/forum/topic/photoacoustic-signal-strength#post-766 Wed, 19 Sep 2012 12:30:43 +0000 bencox 766@http://www.k-wave.org/forum/ <p>Hi Manojit,</p> <p>First quick question: are you doing the example in 3D or 2D? In 2D you'll only get 1/sqrt(r) fall off.</p> <p>Ben </p> http://www.k-wave.org/forum/topic/photoacoustic-signal-strength#post-765 Wed, 19 Sep 2012 09:59:55 +0000 manojitpramanik 765@http://www.k-wave.org/forum/ <p>Hi,<br /> I am trying to use k-wave to simulate how photoacoustic signal look like. I have a basic question on the pressure wave strength it generates. For example I am doing a simple simulation with one point source and one point detector. Assuming the point source generates spherical pressure wave it should have a 1/r decay. Now first I take a point source and a detector with a distance r1 and generates PA signal say s1 and then I put the source and the detector at a distance r2 and gets a signal s2. I was expecting the max(s2)/max(s1) ~= r1/r2. But I don't see this happening. Could you explain where I am doing the mistake?</p> <p>thanks<br /> manojit </p>