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		<title>k-Wave User Forum &#187; Topic: Rotation of US linear transducer</title>
		<link>http://www.k-wave.org/forum/topic/rotation-of-us-linear-transducer-1</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
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		<pubDate>Sun, 31 May 2026 15:20:52 +0000</pubDate>
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			<title>bencox on "Rotation of US linear transducer"</title>
			<link>http://www.k-wave.org/forum/topic/rotation-of-us-linear-transducer-1#post-8553</link>
			<pubDate>Fri, 17 Jun 2022 15:01:35 +0000</pubDate>
			<dc:creator>bencox</dc:creator>
			<guid isPermaLink="false">8553@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Thanks for posting the solution, Gwansuk!
&#60;/p&#62;</description>
		</item>
		<item>
			<title>Gwansuk on "Rotation of US linear transducer"</title>
			<link>http://www.k-wave.org/forum/topic/rotation-of-us-linear-transducer-1#post-8544</link>
			<pubDate>Thu, 26 May 2022 20:10:09 +0000</pubDate>
			<dc:creator>Gwansuk</dc:creator>
			<guid isPermaLink="false">8544@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi&#60;br /&#62;
I have solved this issue by creating a rotating sensor.mask. sensor.mask and its index were copied from transducer.mask and its index members.&#60;br /&#62;
It would be very helpful if you have a better way.&#60;/p&#62;
&#60;p&#62;Thanks
&#60;/p&#62;</description>
		</item>
		<item>
			<title>Gwansuk on "Rotation of US linear transducer"</title>
			<link>http://www.k-wave.org/forum/topic/rotation-of-us-linear-transducer-1#post-8538</link>
			<pubDate>Fri, 20 May 2022 22:07:43 +0000</pubDate>
			<dc:creator>Gwansuk</dc:creator>
			<guid isPermaLink="false">8538@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hello,&#60;/p&#62;
&#60;p&#62;I am trying to get b-mode images by rotating the 1D linear array probe.&#60;br /&#62;
does anybody know how to rotate transducer.mask?&#60;br /&#62;
I don't know how to handle transducer class, so&#60;br /&#62;
I calculate the sensor.mask coordinate of elements after rotating certain deg of angle.&#60;/p&#62;
&#60;p&#62;cos(theta) sin(theta)&#60;br /&#62;
-sin(theta) cos(theta)&#60;/p&#62;
&#60;p&#62;Any method or hint would be appreciated.&#60;/p&#62;
&#60;p&#62;Best,
&#60;/p&#62;</description>
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