<?xml version="1.0" encoding="UTF-8"?>
<!-- generator="bbPress/1.0.2" -->
<rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom">
	<channel>
		<title>k-Wave User Forum &#187; Topic: source.p</title>
		<link>http://www.k-wave.org/forum/topic/sourcep</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
		<language>en-US</language>
		<pubDate>Wed, 13 May 2026 01:42:49 +0000</pubDate>
		<generator>http://bbpress.org/?v=1.0.2</generator>
		<textInput>
			<title><![CDATA[Search]]></title>
			<description><![CDATA[Search all topics from these forums.]]></description>
			<name>q</name>
			<link>http://www.k-wave.org/forum/search.php</link>
		</textInput>
		<atom:link href="http://www.k-wave.org/forum/rss/topic/sourcep" rel="self" type="application/rss+xml" />

		<item>
			<title>bencox on "source.p"</title>
			<link>http://www.k-wave.org/forum/topic/sourcep#post-5616</link>
			<pubDate>Fri, 29 Jul 2016 01:02:42 +0000</pubDate>
			<dc:creator>bencox</dc:creator>
			<guid isPermaLink="false">5616@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Good question. Sources in k-Wave can raise non-trivial issues, but if you want a one-word answer, it is dx^2 not 1 m^2. For example, a pressure source of p Pascals applied evenly over a plane of M*M pixels of size dx^2, (in other words a total force of p*M^2*dx^2 Newtons) will be approximated well by using a weight of p at each source point.&#60;/p&#62;
&#60;p&#62;There is another aspect to be aware of. For initial pressure distributions, defined using &#60;code&#62;source.p0&#60;/code&#62;, or sufficiently long time-varying sources, defined using &#60;code&#62;source.p&#60;/code&#62;, the units will stay consistent. So if &#60;code&#62;source.p0&#60;/code&#62; or &#60;code&#62;source.p&#60;/code&#62; are defined in Pascals, then the measured signal will also be in Pascals. However, if the duration of the time-varying source is too short - comparable to &#60;code&#62;dx/medium.sound_speed&#60;/code&#62; then the measured amplitude will be lower than expected. If this is your situation I can explain further, but it may take quite a long post.&#60;/p&#62;
&#60;p&#62;Also remember that when applying an initial pressure distribution, the resulting wave travels both outward and inward (or both left and right in the 1D case), so a factor of 2 may be required, depending on what you are trying to model.&#60;/p&#62;
&#60;p&#62;Hope that helps,&#60;br /&#62;
Ben
&#60;/p&#62;</description>
		</item>
		<item>
			<title>maryam.parto on "source.p"</title>
			<link>http://www.k-wave.org/forum/topic/sourcep#post-5585</link>
			<pubDate>Fri, 08 Jul 2016 19:50:22 +0000</pubDate>
			<dc:creator>maryam.parto</dc:creator>
			<guid isPermaLink="false">5585@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi&#60;br /&#62;
I want to know that the pressure I define for a source point is force applied over an area of one meter squared or an area of one dx squared?&#60;br /&#62;
Thanks for your attention.
&#60;/p&#62;</description>
		</item>

	</channel>
</rss>
