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		<title>k-Wave User Forum &#187; Topic: source.sxx, source.syy, source.sxy, source.sxz, source.syz</title>
		<link>http://www.k-wave.org/forum/topic/sourcesxx-sourcesyy-sourcesxy-sourcesxz-sourcesyz</link>
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		<pubDate>Tue, 12 May 2026 22:31:09 +0000</pubDate>
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			<title>fengfan9999 on "source.sxx, source.syy, source.sxy, source.sxz, source.syz"</title>
			<link>http://www.k-wave.org/forum/topic/sourcesxx-sourcesyy-sourcesxy-sourcesxz-sourcesyz#post-7056</link>
			<pubDate>Fri, 20 Sep 2019 17:17:56 +0000</pubDate>
			<dc:creator>fengfan9999</dc:creator>
			<guid isPermaLink="false">7056@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi Patrick, &#60;/p&#62;
&#60;p&#62;Thanks for your answer! I think you're right because your answer corresponds with Fabrice Prieur, and Stefan Catheline's paper which used a stress tensor model was similar to yours. Please let me know more if you find something new, thanks again!&#60;/p&#62;
&#60;p&#62;Best Regards,&#60;br /&#62;
Fan
&#60;/p&#62;</description>
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			<title>Patrick on "source.sxx, source.syy, source.sxy, source.sxz, source.syz"</title>
			<link>http://www.k-wave.org/forum/topic/sourcesxx-sourcesyy-sourcesxy-sourcesxz-sourcesyz#post-7051</link>
			<pubDate>Wed, 18 Sep 2019 20:40:01 +0000</pubDate>
			<dc:creator>Patrick</dc:creator>
			<guid isPermaLink="false">7051@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hello,&#60;/p&#62;
&#60;p&#62;Take a look at this figure: &#60;a href=&#34;http://www.iue.tuwien.ac.at/phd/smirnov/img714.png&#34; rel=&#34;nofollow&#34;&#62;http://www.iue.tuwien.ac.at/phd/smirnov/img714.png&#60;/a&#62;. This is the components of the stress tensor (s in sxz stands for sigma). From the figure, you can see that the first coordinate identifies the direction and the second coordinate specifies the plane. So sxz is the stress in the x direction on the z plane.&#60;/p&#62;
&#60;p&#62;Moreover, to enforce 0 net torque, the stress tensor must be symmetric, this means switching the coordinates should not change the value, so sxz = szx. (I am not certain that this is the case inside of k-Wave, but is the case in much of soft condensed matter physics).&#60;/p&#62;
&#60;p&#62;Hope this helps,&#60;/p&#62;
&#60;p&#62;PC
&#60;/p&#62;</description>
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			<title>fengfan9999 on "source.sxx, source.syy, source.sxy, source.sxz, source.syz"</title>
			<link>http://www.k-wave.org/forum/topic/sourcesxx-sourcesyy-sourcesxy-sourcesxz-sourcesyz#post-7049</link>
			<pubDate>Mon, 16 Sep 2019 19:53:57 +0000</pubDate>
			<dc:creator>fengfan9999</dc:creator>
			<guid isPermaLink="false">7049@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi Dr. Treeby,&#60;/p&#62;
&#60;p&#62;I met trouble with shear wave simulation (pstdElastic2D &#38;amp; pstdElastic3D). The question is how do you define the stress in k-wave? For example, if I set up source.sxz, is x the perpendicular plane or the parallel direction? Thanks!&#60;/p&#62;
&#60;p&#62;Best Regards,&#60;br /&#62;
Fan
&#60;/p&#62;</description>
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