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		<title>k-Wave User Forum &#187; Topic: what&#039;s the difference between dB/(MHz^y cm) and dB/(MHz/cm) ?</title>
		<link>http://www.k-wave.org/forum/topic/whats-the-difference-between-dbmhzy-cm-and-dbmhzcm</link>
		<description>Support for the k-Wave MATLAB toolbox</description>
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		<pubDate>Wed, 13 May 2026 09:52:08 +0000</pubDate>
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			<title>wang_feng_2020 on "what&#039;s the difference between dB/(MHz^y cm) and dB/(MHz/cm) ?"</title>
			<link>http://www.k-wave.org/forum/topic/whats-the-difference-between-dbmhzy-cm-and-dbmhzcm#post-7366</link>
			<pubDate>Sat, 04 Apr 2020 06:17:25 +0000</pubDate>
			<dc:creator>wang_feng_2020</dc:creator>
			<guid isPermaLink="false">7366@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Thank you,Brad.&#60;br /&#62;
Maybe they think  dB/（MHz/cm） is same as dB/(MHz^y cm).Iin one paper,I find this:&#34;The attenuation coefficient (α) varies with frequency as:α=a * f ^ b.where coefficient a has units of Np/cm/MHz, f is the frequency in MHz, and coefficient b is dimensionless. &#34;
&#60;/p&#62;</description>
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			<title>Bradley Treeby on "what&#039;s the difference between dB/(MHz^y cm) and dB/(MHz/cm) ?"</title>
			<link>http://www.k-wave.org/forum/topic/whats-the-difference-between-dbmhzy-cm-and-dbmhzcm#post-7358</link>
			<pubDate>Fri, 03 Apr 2020 15:07:49 +0000</pubDate>
			<dc:creator>Bradley Treeby</dc:creator>
			<guid isPermaLink="false">7358@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi wang_feng_2020,&#60;/p&#62;
&#60;p&#62;That doesn't sound dimensionally correct. Maybe they listed the units wrongly?&#60;/p&#62;
&#60;p&#62;Brad.
&#60;/p&#62;</description>
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			<title>wang_feng_2020 on "what&#039;s the difference between dB/(MHz^y cm) and dB/(MHz/cm) ?"</title>
			<link>http://www.k-wave.org/forum/topic/whats-the-difference-between-dbmhzy-cm-and-dbmhzcm#post-7357</link>
			<pubDate>Fri, 03 Apr 2020 12:02:30 +0000</pubDate>
			<dc:creator>wang_feng_2020</dc:creator>
			<guid isPermaLink="false">7357@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;thank you,Bradley.&#60;br /&#62;
in a database,the unit of absorption is dB/（MHz/cm） and b is 1.5.(i don't know whwther b is y ) But if b is y,  how do I convert units to  dB/(MHz^y cm)?
&#60;/p&#62;</description>
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			<title>Bradley Treeby on "what&#039;s the difference between dB/(MHz^y cm) and dB/(MHz/cm) ?"</title>
			<link>http://www.k-wave.org/forum/topic/whats-the-difference-between-dbmhzy-cm-and-dbmhzcm#post-7348</link>
			<pubDate>Wed, 01 Apr 2020 15:22:18 +0000</pubDate>
			<dc:creator>Bradley Treeby</dc:creator>
			<guid isPermaLink="false">7348@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;Hi wang_feng_2020,&#60;/p&#62;
&#60;p&#62;The absorption in many materials follows a frequency power law of the form a0 * f ^ y. Here a0 is in units of dB/(MHz^y cm), and f is frequency in units of MHz. &#60;/p&#62;
&#60;p&#62;If y = 1, there is a linear dependence on frequency, and the units would then be dB/(MHz cm).&#60;/p&#62;
&#60;p&#62;Brad.
&#60;/p&#62;</description>
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			<title>wang_feng_2020 on "what&#039;s the difference between dB/(MHz^y cm) and dB/(MHz/cm) ?"</title>
			<link>http://www.k-wave.org/forum/topic/whats-the-difference-between-dbmhzy-cm-and-dbmhzcm#post-7338</link>
			<pubDate>Tue, 31 Mar 2020 12:13:00 +0000</pubDate>
			<dc:creator>wang_feng_2020</dc:creator>
			<guid isPermaLink="false">7338@http://www.k-wave.org/forum/</guid>
			<description>&#60;p&#62;In some paper,the unit of attenuation is dB/(MHz/cm).what's the difference between dB/(MHz^y cm) and dB/(MHz/cm) and what does y mean?
&#60;/p&#62;</description>
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